0=-16x^2+96x+432

Solution for 0=-16x^2+96x+432 equation:

0=-16x^2+96x+432

We move all terms to the left:

0-(-16x^2+96x+432)=0

We add all the numbers together, and all the variables

-(-16x^2+96x+432)=0

We get rid of parentheses

16x^2-96x-432=0

a = 16; b = -96; c = -432;
Δ = b2-4ac
Δ = -962-4·16·(-432)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-192}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+192}{2*16}=\frac{288}{32}
=9
$